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for you, you can turn them off with

思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。。同城约会对此有专业解读

Requires C++20. Axiom is the only dependency (included as a submodule).，更多细节参见服务器推荐

let pixel = image.get(0, 0);